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Publicada porGonzalo Lorenzo Ramírez Paz Modificado hace 9 años
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1 SOLVING RATIONAL EQUATIONS SIMPLIFYING RATIONAL EXPRESSIONS Standards 4, 7, 15, 25 ADDING RATIONAL EXPRESSIONS PROBLEM 1 RATIONAL EXPRESSIONS PROBLEM 2 FINDING THE LCD END SHOW PRESENTATION CREATED BY SIMON PEREZ. All rights reserved
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2 STANDARD 4: Students factor polynomials representing the difference of squares, perfect square trinomials, and the sum and difference of two cubes. STANDARD 7 Students add, subtract, multiply, divide, reduce, and evaluate rational expressions with monomial and polynomial denominators and simplify complicated rational expressions, including those with negative exponents in the denominator. STANDARD 15: Students determine whether a specific algebraic statement involving rational expressions, radical expressions, or logarithmic or exponential functions is some-times true, always true, or never true. STANDARD 25: Students use properties from number systems to justify steps in combining and simplifying functions. ALGEBRA II STANDARDS THIS LESSON AIMS: PRESENTATION CREATED BY SIMON PEREZ. All rights reserved
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3 ESTÁNDAR 4: Los estudiantes factorizan diferencias de cuadrados, trinomios cuadrados perfectos, y la suma y diferencia de dos cubos. ESTÁNDAR 7: Los estudiantes suman, restan, multiplican, dividen, reducen y evalúan expresiones racionales con monomios y polinomios en los denominadores y simplifican expresiones racionales, incluyendo aquellas con exponentes negativos en el denominador. ESTÁNDAR 15: Los estudiantes determinan si un estatuto algebraico específico involucrando expresiones racionales, expresiones radicales, o funciones logarítmicas o exponenciales es verdadero algunas veces, siempre o nunca. ESTÁNDAR 25: Los estudiantes usan propiedades de los sistemas numéricos para combinar y simplificar funciones. PRESENTATION CREATED BY SIMON PEREZ. All rights reserved
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4 Simplify each expression: x + 3 2x - 2 2 x -1 2 5x + 15.. 2x - 2 2 5x + 15 x + 3 x -1 2 = 5(x+3) = x -1 2 x + 3 2( ) x -1 2 = 2 5 x + 5 27x + 8 3 9x - 6x + 4 2.. = 27x + 8 3 x + 5 9x - 6x + 4 2 (3x+2)( ) 9x - 6x + 4 2 x + 5 9x - 6x + 4 2 (3x +2)(x + 5) (5) x (2) 3x x +3x +2 (5) + F O I L = 3x + 17x + 10 2 = 3x +15x + 2x + 10 2 = = = Standards 4, 7, 15, 25 PRESENTATION CREATED BY SIMON PEREZ. All rights reserved
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5 Find the Least Common Denominator for these denominators Standards 4, 7, 15, 25 8xy z 4 2 4x z 2 5 2x y 32 32 8xy z 4 2 4x z 2 5 = 2x y 32 =2 xy z 4 2 3 =2 x z 2 5 2 We choose each one of the different numbers and variables with the greatest exponent. 2 3 x 3 y 4 z 5 = 8 x 3 y 4 z 5 LCD: 7xy z 5 6 27x z 8 4 9x y z 57 We choose each one of the different numbers and variables with the greatest exponent. 3 3 x 8 y 7 z 6 = 189 x 8 y 7 z 6 LCD: 9x y z 57 7xy z 5 6 27x z 8 4 7xy z 5 6 = = 3 x y z 5 7 2 = 3 x z 8 4 3 7 PRESENTATION CREATED BY SIMON PEREZ. All rights reserved
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6 Add the following rational expressions: 3x x - 3 5x x + 3 x -9 2 x -7 + - Find the LCD x - 3 x + 3 x -9 2 = (x+3)(x-3) = x -9 2 3x x - 3 5x x + 3 x -9 2 x -7 + - 3x x - 3 5x x + 3 x -9 2 x -7 + - = x + 3 x - 3 x -9 2 2 2 x -7 3x +9x 2 5x - 15x 2 + - = = 2 - (x – 7) 3x +9x 2 + x -9 2 = 2 - x + 7 5x - 15x 2 3x + 9x 2 + = x -9 2 2 2 5x + 3x - 15x + 9x - x + 7 = x -9 2 8x – 7x + 7 2 Get the same denominator for all fractions. Standards 4, 7, 15, 25 PRESENTATION CREATED BY SIMON PEREZ. All rights reserved
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7 Solve the following rational equation: 6x x - 2 4x x + 2 x -4 2 30 + = Find the LCD x - 2 x + 2 x -4 2 = (x+2)(x-2) Multiply both sides by the LCD: 6x x - 2 4x x + 2 x -4 2 30 + = OR x -4 2 (x+2)(x-2) 6x x - 2 4x x + 2 x -4 2 30 + = (x+2)(x-2) x -4 2 (x-2)(4x) + (x+2)(6x) = 30 4x – 8x + 6x +12x = 30 2 2 10x + 4x = 30 2 -30 10x + 4x – 30 = 0 2 2 2 2 5x + 2x – 15 = 0 Standards 4, 7, 15, 25 Note: This equation can’t have values at x=2, and x= -2, because with those values we have division by zero; which is not defined! PRESENTATION CREATED BY SIMON PEREZ. All rights reserved
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8 We substitute values: 5 5 2 2 -15 + - x = -b b - 4ac 2a2a 2 +_ = -( ) ( ) - 4( )( ) 2( ) 2 +_ x = -2 4 + 300 10 +_ x -2 304 = 10 +_ x -2 17.43 = 10 +_ x -2+17.43 = 10 x 15.43 = x 1.54 x 10 -19.43 = x -1.94 x -2 -17.43 = 10 x Using the Quadratic Formula: a= 5 b= 2 c= -15 = -2 4 -20(-15) 10 +_ x 2 5x + 2x – 15 = 0 Standards 4, 7, 15, 25 PRESENTATION CREATED BY SIMON PEREZ. All rights reserved
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9 Solve the following rational equation: 7x x - 1 6x x + 1 x -1 2 32 + = Find the LCD x - 1 x + 1 x -1 2 = (x+1)(x-1) Multiply both sides by the LCD: 7x x - 1 6x x + 1 x -1 2 32 + = OR x -1 2 (x+1)(x-1) 7x x - 1 6x x + 1 x -1 2 32 + = (x+1)(x-1) x -1 2 (x-1)(6x) + (x+1)(7x) = 32 6x – 6x + 7x +7x = 32 2 2 13x + x = 32 2 -32 13x + x – 32 = 0 2 Standards 4, 7, 15, 25 Note: This equation can’t have values at x=1, and x= -1, because with those values we have division by zero; which is not defined! PRESENTATION CREATED BY SIMON PEREZ. All rights reserved
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10 We substitute values: 13 1 1 -32 + - x = -b b - 4ac 2a2a 2 +_ = -( ) ( ) - 4( )( ) 2( ) 2 +_ x = -1 1 +1664 26 +_ x -1 1665 = 26 +_ x -1 40.80 = 26 +_ x -1+40.80 = 26 x 39.80 = x 1.5 x 26 -41.80 = x -1.6 x -1 -40.80 = 26 x Using the Quadratic Formula: a= 13 b= 1 c= -32 = -1 1 -52(-32) 26 +_ x 2 13x + x – 32 = 0 Standards 4, 7, 15, 25 PRESENTATION CREATED BY SIMON PEREZ. All rights reserved
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