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Publicada porMaría Jesús Hidalgo Casado Modificado hace 8 años
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Electrical Power & Machines “Electrical Engineering Dept” Prepared By: Dr. Sahar Abd El Moneim Moussa 1
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CLASSIFICATION OF T.L ACCORDING TO LENGTH According to length, T.L. can be classified as follows: 1- Short T.L. : up to 80 km( 50 miles) 2- Medium T.L. : >80 km <240 km 3- Long T.L. : > 240 km Dr. Sahar Abd El Moneim Moussa3
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Representation of a transmission line by a two port Network Dr. Sahar Abd El Moneim Moussa4
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The General equation is : V s = A V R + B I R I S = C V R + D I R In Matrix Form : V S A B V R I S = C D I R Dr. Sahar Abd El Moneim Moussa5
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Where, V S = sending- end phase (line –to-neutral) voltage V R = receiving - end phase (line –to-neutral) voltage I s = sending-end phase current. I R = receiving-end phase current. Dr. Sahar Abd El Moneim Moussa6
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1- Short OHTL: (up to 80 km) Equivalent Circuit: Dr. Sahar Abd El Moneim Moussa7
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The General equation is: V s = V R + Z I R I s =I R In Matrix Form : V S = 1 Z V R I S = 0 1 I R Dr. Sahar Abd El Moneim Moussa8
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The ABCD Parameters of a short T.L: A=D=1, B=Z, C=0 Where, Z = R+ jX L = zL = rL +jxL Ω Z= total series impedance per-phase in ohms. z = series impedance of one conductor in ohms per unit length X L = total inductive reactance of one conductor in ohms. X = inductive reactance of one conductor in ohms per unit length L = length of the line. Dr. Sahar Abd El Moneim Moussa9
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Where, V RNL = magnitude of receiving end voltage at no-load V RFL = magnitude of receiving end voltage at full-load with constant Vs Dr. Sahar Abd El Moneim Moussa11
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Example 9: A three-phase, 50 Hz overhead 40 km T.L. has a line voltage of 23 kV at the receiving end, a total impedance of 2.48+j6.57 per phase, and a load of 9 MW with receiving end lagging pf of 0,85. Calculate: a) Line to neutral voltage at the sending end b) Efficiency of the line c) Voltage regulation of the line Dr. Sahar Abd El Moneim Moussa12
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2- Medium OHTL: ( from 80 km to 240 km) The medium OHTL can be represented either by: i. - equivalent circuit ii. T- equivalent circuit Dr. Sahar Abd El Moneim Moussa15
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i- - Circuit: Equivalent Circuit: Dr. Sahar Abd El Moneim Moussa16 j X VSVS VRVR ISIS R C/2 I cs I I CR IrIr
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i- T- Circuit: Equivalent Circuit: Dr. Sahar Abd El Moneim Moussa19
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Example 10 A 50 Hz 200 km, transmission line has 132 kV between the lines at the receiving end and has per phase R=0.1 /km, L=0.828 mH/km And C= 0.005 F/km. the line is supplying a load of 30MW at 0.85 lagging pf. Find using approximated -model: a) A,B,C and D constants of the line b) V and I at the sending end of the line c) and VR of the line Dr. Sahar Abd El Moneim Moussa23
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Solution: Z= R+ j L= 0.1 x 200 + j 2 x x 50 x 0.828 x 10 -3 x 200 = 20 + j 52 = 55 69 Y= j C= j 2 x x 50 x 0.005 x 10 -6 x 200 = j 314 x 10 -6 mho= 314x10 -6 90 mho YZ= -0.016 + j 0.00628 ( 1) a) A= D= 1 B= Z= 20 + j 52 = 55 69 C= Y = j 314 x 10 -6 mho= 314x10 -6 90 mho Dr. Sahar Abd El Moneim Moussa24
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